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NH Students Society
Nh Students Society is a sub organization established under the RNH Welfare Society that provides services which enable outstanding student experiences. The Society organizes events and opportunities for Trainees to become acquainted with other employees of the Group. The objective of the Society is making a platform for trainees in developing their organizing skills, team work and interacting with each other well. All Trainees are required to be members of society during their training period. The Society is fully administrated by the Trainees in consultation with the RNH Welfare Society.
Our Vision
To be a union to develop values & Professional confidence of students by encouraging their creativity & good behavior.
Our Mission
To build responsible leaders within the organization to promote the value that represent good character in all trainees.
Our Values
Team Spirit
Supportive
Responsible
Trust
Quality
Creativity
Committee
President
Avinesh Allang
077-3258704
Vice President
Tharushi Nethsarani
077-5685386
Secretary
Hansani Kaushalya
071-6940018
Treasurer
Viraj Madushanka
071-6061921
Committee Members
- – Education Committee – Thusitha Chandana – 0788447678
- – Sports Committee – Ruwani Kumari & Chamoch Pulinda – 0715661436
- – IT Committee – Thamasha Liyanage – 0702085331
- – CSR Committee – Madusha Hasangani – 0712602988
CA Exam Time Table
This program provides a supportive and positive learning experience and would convey you an occasion to serve in many capacities. By participating in all functions, you will receive a pleasing experience in developing communication and leadership skills, resulting in greater self-confidence and personal growth.
Consists of the Programme
- – The ice breaker speech
- – Telephone Etiquettes
- – Interview Etiquettes
- – Meeting Etiquettes
- – Organize your Speech
Important Links
Question of the month
ABC has produced its draft financial statements for the year ended 31 March 2016 and two issues have arisen:
- 1. On 1 March 2016, ABC factored (sold) LKR 2 million of trade receivables to XYZ. ABC received an immediate payment of LKR 1·8 million and credited this amount to receivables and charged LKR 200,000 to administrative expenses. ABC will receive further amounts from XYZ depending on how quickly XYZ collects the receivables. XYZ will charge a monthly administration fee of LKR10,000 and 2% per month on its outstanding balance with ABC. Any receivables not collected after four months would be sold back to ABC; however, ABC expects all customers to settle in full within this period. None of the receivables were due or had been collected by 31 March 2016.
- 2. On 1 April 2014, ABC sold a property which had a carrying amount of LKR 3·5 million to a property company for LKR 5 million and recorded a profit of LKR1·5 million on the disposal. Part of the terms of the sale are that ABC will rent the property for a period of five years at an annual rental of LKR 400,000. At the end of this period, the property company will sell the property through a real estate company/property agent at its fair value which is expected to be approximately LKR 6·5 million. ABC will be given the opportunity to repurchase the property (at its fair value) before it is put on the open market. All of the above amounts are deemed to be at commercial values.
You are required to explain and quantify where appropriate, how ABC should account for the above two issues in its financial statements for the year ended 31 March 2016.
Answer for the previous month question
Test your IQ
Question #1
Answer: b
35% of a circle is 126º. Th erefore, the angle for M will be 90º. L-M is 36. Since K+L+M=1440, which is 4 times more than 360, L-M will be 36º4=144.
Question #2
Answer: d
The pattern in the question goes like this: the shaded area has the largest number of sides.
The first row has two rectangles and a triangle. The largest number of sides is rectangle. Hence the shaded area for the first row has rectangle.
The second row has a pentagon as the largest number of sides. So the shaded area for the second row has a pentagon.
The third row has an octagon shape as the largest number of sides. So, the shaded area for the third row must be an hexagon.
The fourth row has a rectangle as the largest number of sides. So, the shaded are for the fourth row is rectangle.
Question #3
Answer: a
The pattern goes like this: Pick the last letter in the shaded row and the first letter in shaded column and com e up with a two letter expression.
1st row: The last letter: M
2nd row: The last letter: K
3rd row: The last letter: N
1st column: The first letter: K
2nd column: The first lett er: M
3rd column: The first lette r: N
4th column: The first lette r: L
For X, we have to look at the last letter in the 1st row (M) and the first letter in the 4th column (L). So, the result is ML.
For Y, we have to look at the last letter in the 3rd row (N) and the first let ter in the 3rd column (N). So, the resul t is NN.
Question #4
Answer: a
The pattern goes like this: add the digits and follow an increasing patter n in clockwise.
874: 8+7+4=19
6572: 6+5+7+2=20
984: 9+8+4=21
43492=4+3+4+9+2=22
So the digits of the last n umber must add up to 23, which is 4388: 4+3+8 +8=23.
Question #5
Answer: c
The word “Bee†indicates that the last two digits in a number must be th e same. The only possible number is 6 55. This shows that letter “B†corresponds with number “6†and letter “E†correspondds to number “5â€. Since “TIE†ends with E whic h is 5, there are two alternatives: 975 and 875. There are two numbers whose first digit starts with 8 and one number whose first digit starts with 9 in Group I. This indicates that number “8†corresponds with letter “T†and number “9†corresponds with letter “P†in Group II. Therefore, the result for “TIE†is “875â€.
Puzzles
